## FANDOM

230 Pages

The nonnegative integer solutions for the following equations:

$x^3+1=y^2$

 x y 0 1 2 3

$\frac{x(x+1)}{2}=\frac{y(y+1)(y+2)}{6}$

 x y 0 0 1 1 4 3 13 8 47 18 9E 2X

$x^2=\frac{y(y+1)(y+2)}{6}$

 x y 0 0 1 1 2 2 E8 40

$\frac{x(x+1)}{2}=\frac{y(y+1)(2y+1)}{6}$

 x y 0 0 1 1 X 5 11 6 459 71

$x^2=\frac{y(y+1)(2y+1)}{6}$

 x y 0 0 1 1 5X 20

$2^x-7=y^2$

 x y 3 1 4 3 5 5 7 E 13 131

$x!+1=y^2$

 x y 4 5 5 E 7 5E

$x\#=y(y+1)$

 x y 2 1 3 2 5 5 7 12 15 4E6

$x^2-ny^2=1$

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